4800=3y^2

Solution for 4800=3y^2 equation:

4800=3y^2

We move all terms to the left:

4800-(3y^2)=0

a = -3; b = 0; c = +4800;
Δ = b2-4ac
Δ = 02-4·(-3)·4800
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*-3}=\frac{-240}{-6}
=+40
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*-3}=\frac{240}{-6}
=-40
$